Alfred, Allegany, New York, United States of America
| Latitude | 42°15'22.00"N |
| Longitude | 77°47'23.00"W |
| County | Allegany |
| State/ Province | New York |
| Country | United States of America |
| Enclosed By | |
|---|---|
| Allegany | |
| Place Encloses |
Web Links
| Type | Description |
|---|---|
| Wikipedia Article | Alfred, New York (Wikipedia) [Click to Go] |